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To sum all working days knowing the employees involved in a particular project to know the cost generated for their work I did: CREATE TABLE Employee( Employee ID INTEGER NOT NULL PRIMARY KEY, Name VARCHAR(30) NOT NULL, Sex CHAR(1) NOT NULL, Address VARCHAR(80) NOT NULL, Security VARCHAR(15) NOT NULL ); CREATE TABLE Departments ( Dept ID INTEGER NOT NULL PRIMARY KEY, Dept Name VARCHAR(30) NOT NULL ); CREATE TABLE `Dept-Employee`( Employee ID INTEGER NOT NULL, Dept ID INTEGER NOT NULL, CONSTRAINT fk_Dept ID FOREIGN KEY (Dept ID) REFERENCES Departments(Dept ID), CONSTRAINT fk_Employee ID FOREIGN KEY (Employee ID) REFERENCES Employee(Employee ID) ); CREATE TABLE `Dept-Manager`( Employee ID INTEGER NOT NULL, Dept ID INTEGER NOT NULL, CONSTRAINT fk_Dept IDs FOREIGN KEY (Dept ID) REFERENCES Departments(Dept ID), CONSTRAINT fk_Employee IDs FOREIGN KEY (Employee ID) REFERENCES Employee(Employee ID) ); CREATE TABLE Jobs ( Job ID INTEGER NOT NULL PRIMARY KEY, Job Name VARCHAR(30) NOT NULL, Job Salary DOUBLE(15,3) NOT NULL default '0.000', Job Salaryper Day DOUBLE(15,3) NOT NULL default '0.000', Dept ID INTEGER NOT NULL ); CREATE TABLE `Jobs-Employee`( Employee ID INTEGER NOT NULL, Job ID INTEGER NOT NULL, CONSTRAINT fk_Job IDs FOREIGN KEY (Job ID) REFERENCES Jobs(Job ID), CONSTRAINT fk_Employee IDss FOREIGN KEY (Employee ID) REFERENCES Employee(Employee ID) ); CREATE TABLE Project( Project ID INTEGER NOT NULL PRIMARY KEY, Project Desc VARCHAR(200) NOT NULL, Start Date DATE NOT NULL, End Date DATE NOT NULL, Days Of Work INTEGER NOT NULL, No Employees INTEGER NOT NULL, Estimated Cost DOUBLE(15,3) NOT NULL default '0.000', Real Cost DOUBLE(15,3) NOT NULL default '0.000' ); CREATE TABLE `Project-Employee`( Project ID INTEGER NOT NULL, Employee ID INTEGER NOT NULL, Note VARCHAR(200), Days Work INTEGER NOT NULL, CONSTRAINT fk_Project IDsss FOREIGN KEY (Project ID) REFERENCES Project(Project ID), CONSTRAINT fk_Employee IDsss FOREIGN KEY (Employee ID) REFERENCES Employee(Employee ID) ); INSERT INTO `Departments` VALUES (1, 'Outsourcing'); INSERT INTO `Departments` VALUES (2, 'Technician'); INSERT INTO `Departments` VALUES (3, 'Administrative'); INSERT INTO `Jobs` VALUES (1, 'welder' ,500.550,16.7 ,2); INSERT INTO `Jobs` VALUES (2, 'turner' ,500.100,16.67,2); INSERT INTO `Jobs` VALUES (3, 'assistant' ,650.100,21.67,2); INSERT INTO `Jobs` VALUES (4, 'supervisor',800.909,26.70,3); INSERT INTO `Jobs` VALUES (5, 'manager' ,920.345,30.68,3); INSERT INTO `Jobs` VALUES (6, 'counter' ,520.324,17.35,1); INSERT INTO `Employee` VALUES (10, 'Joe', 'M', 'Anywhere', '927318344'); INSERT INTO `Employee` VALUES (20, 'Moe', 'M', 'Anywhere', '827318322'); INSERT INTO `Employee` VALUES (30, 'Jack', 'M', 'Anywhere', '927418343'); INSERT INTO `Employee` VALUES (40, 'Marge','F', 'Evererre', '127347645'); INSERT INTO `Employee` VALUES (50, 'Greg' ,'M', 'Portland', '134547633'); INSERT INTO `Dept-Employee` VALUES (10,1); INSERT INTO `Dept-Employee` VALUES (20,2); INSERT INTO `Dept-Employee` VALUES (30,3); INSERT INTO `Dept-Employee` VALUES (40,1); INSERT INTO `Dept-Employee` VALUES (50,3); INSERT INTO `Jobs-Employee` VALUES (10,3); INSERT INTO `Jobs-Employee` VALUES (20,3); INSERT INTO `Jobs-Employee` VALUES (30,4); INSERT INTO `Jobs-Employee` VALUES (40,6); INSERT INTO `Jobs-Employee` VALUES (50,5); INSERT INTO `Project` VALUES (1, 'The very first', '2008-7-04' , '2008-7-24' , 20, 5, 3000.50, 2500.00); INSERT INTO `Project` VALUES (2, 'Second one pro', '2008-8-01' , '2008-8-30' , 30, 5, 6000.40, 6100.40); INSERT INTO `Project-Employee` VALUES (1, 10, 'Worked all days' , 20); INSERT INTO `Project-Employee` VALUES (1, 20, 'Worked just in defs', 11); INSERT INTO `Project-Employee` VALUES (1, 30, 'Worked just in defs', 17); INSERT INTO `Project-Employee` VALUES (1, 40, 'Contability ' , 8); INSERT INTO `Project-Employee` VALUES (1, 50, 'Managed the project', 8); CREATE VIEW `Emp-Job` as SELECT e.*,ID FROM Employee e,`Jobs-Employee` j WHERE e. Employee ID; CREATE VIEW `employee_pay` as select e.*, j.jobname, j.jobsalary, j.jobsalaryperday from `Emp-Job` e inner join `Jobs` j on e. Job ID; create view project_pay as select pe.projectid, pe.employeeid, pe.dayswork, e.jobsalaryperday, (e.jobsalaryperday * dayswork) as total_salary from `Project-Employee` pe inner join `employee_pay` e on e.employeeid = pe.employeeid One change I would prefer is to have a primary key named as "id" for every table.So here Employee table will have the primary key - id, not the "Employee ID".

I am doing a database design I want to create a database with information of employees, their jobs, salaries and projects.I want to keep information of the cost of a project (real value of project and the days a employee invested).For through the PK constraint, and allows for the addition of a new role type ("Tertiary" perhaps) in the future.To get the total amount of the cost of a project and have it for future Work quote, I would just sum the working days of each job for each employee in an aggregate query.Sometimes, it is required to identify duplicate records and remove them from the table.

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This chapter will describe how to prevent duplicate records occurring in a table and how to remove already existing duplicate records.

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